'Bell weights' A mathematician responds

Andrew Aspland aaspland at y...
Tue Sep 28 17:12:06 BST 2004

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Glad we have cleared up the "quarter of a quarter" problem. Assuming that
bell weights randomly end in any number of pounds from 0 to 27 then there is
a 4/28 = 1/7 probability that the weight will end in 0,7,14 or 28. This is
a reasonable assumption given teh range of weights we are considering but
would not be true for very small bells.

For a ring of six to all end in such a number the probability would be 1/7^6
which is 0.000008499 in other words less than a 1 in 100 000 chance - be
VERY suspisious. Even for a ring of four this is less than a 1 in 2000

For all six bells to end in 0 (Shaftsbury) the probability would be 1/28^6
which is 0.000000002 or around a 1 in 500 000 000 chance. Statistically I
do not believe that Shaftsbury all ended in 0.

For any two bells out of eight to end in 0 is a less than 4% chance - worth

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