> PABS gives us, > > > T^[(2n+3)(n-2)]/5^[2n-4] x n x [(n-4)/2]!.2^[(n-4)/2]/(n-3)! > > Can you just tell us what the numbers are, for say 6 though 16? Ta. > that's the easy bit... 6: 2E7 7: 7E10 8: 1E15 9: 2E20 10: 2E26 11: 1E33 12: 4E40 13: 8E48 14: 1E59 15: 1E68 16: 8E78