[r-t] Monday afternoon puzzle

[Philip Earis]

Me:
"Loads more possibilities on a similar plan must be around.  I'll have a
proper look sometime. Is it possible to get the trick effect on ten
bells with a right-place method, I wonder?"

Right, I've had a bit of a play around to look for treble-dodging royal
methods with the trick half-leads.  This is still fairly preliminary,
but I've found some good stuff. I think it could be effective to splice
essentially the same methods with different half-lead /leadend combos to
focus on the best leads.  Anyway, here we go...

Firstly we have the two methods I posted the other day:
&-5-4-5-3-2-8-56.2.3-2-1,2 1352749608 AB2D2a1c
&-5-4-5-3-2-8-56-3.78-78.1,2 1352749608 AB2D2c

I'm slightly surprised to see that there's never been a royal method
with this overwork. Both methods are fairly static around with half-lead
(especially with the 9ths-place variant), but this could be effective as
the whole idea is to keep pairs of bells together.

A method with the same overwork but that is less static is also
achievable, such as:
&-5-4-5-3-2-8-34.6.5-4-1,2 1352749608 AB2a1c

Varying the overwork, it's possible to use the Bristol-style
hunt-to-a-point start to good effect, also avoiding contiguous places to
produce the clean free-flowing baby:
&-5-4.5-7.36-7-8-6-1-58-1,0 1573920486 Ac

Similarly, the 'raspberry crumble' (or Sussex) start can be used in a
similar style:
&3-5.4-5-36-4.7.38-6-3.4.58-1,2 1648203957 AB2K2c

Finally, given that the whole idea originated with Cambridge, I looked
for methods with a Cambridge start and clean notation around the
half-lead, with an emphasis on chunks of right-place notation. Five
possibilities are given below.

&-3-4-25-3.78.4.7.8-4-5-4-1,0 1426385079 AB1B2
&-3-4-25-38-347-3.4-4.3-4-1,0 1089674523 AB1B2
&-3-4-25-38-347.2.3-4-1-4-1,0 1089674523 AB1B2
&-3-4-25-1.78-7.8-2-45-4-1,0 1426385079 AB1B2a2
&-3-4-25-8-27.34.1-4-1-4-1,0 1089674523 AB1B2


I was also keen to find a completely right-place method.  Following
Richard's assertion that this wouldn't be possible with just quadruple
changes, I experimented a bit with methods similar to those above and
came up with one example:
&-3-4-25-8-27-38-6-347-4-1,2 1648203957 AB1B2

Is it possible to come up with a right-place method that extends
indefinitely with the half-lead property?  Seems unlikely but I'm keen
to see what people do.  A better example of a right-place method would
also be good.




DISCLAIMER:

This communication (including any attachments) is intended for the use of the addressee only and may contain confidential, privileged or copyright material. It may not be relied upon or disclosed to any other person without the consent of the RSC. If you have received it in error, please contact us immediately. Any advice given by the RSC has been carefully formulated but is necessarily based on the information available, and the RSC cannot be held responsible for accuracy or completeness. In this respect, the RSC owes no duty of care and shall not be liable for any resulting damage or loss. The RSC acknowledges that a disclaimer cannot restrict liability at law for personal injury or death arising through a finding of negligence. The RSC does not warrant that its emails or attachments are Virus-free: Please rely on your own screening.