[r-t] Monday afternoon puzzle
Earisp at rsc.org
Fri Jul 1 10:13:04 UTC 2005
"Loads more possibilities on a similar plan must be around. I'll have a
proper look sometime. Is it possible to get the trick effect on ten
bells with a right-place method, I wonder?"
Right, I've had a bit of a play around to look for treble-dodging royal
methods with the trick half-leads. This is still fairly preliminary,
but I've found some good stuff. I think it could be effective to splice
essentially the same methods with different half-lead /leadend combos to
focus on the best leads. Anyway, here we go...
Firstly we have the two methods I posted the other day:
&-5-4-5-3-2-8-56.2.3-2-1,2 1352749608 AB2D2a1c
&-5-4-5-3-2-8-56-3.78-78.1,2 1352749608 AB2D2c
I'm slightly surprised to see that there's never been a royal method
with this overwork. Both methods are fairly static around with half-lead
(especially with the 9ths-place variant), but this could be effective as
the whole idea is to keep pairs of bells together.
A method with the same overwork but that is less static is also
achievable, such as:
&-5-4-5-3-2-8-34.6.5-4-1,2 1352749608 AB2a1c
Varying the overwork, it's possible to use the Bristol-style
hunt-to-a-point start to good effect, also avoiding contiguous places to
produce the clean free-flowing baby:
&-5-4.5-7.36-7-8-6-1-58-1,0 1573920486 Ac
Similarly, the 'raspberry crumble' (or Sussex) start can be used in a
&3-5.4-5-36-4.7.38-6-3.4.58-1,2 1648203957 AB2K2c
Finally, given that the whole idea originated with Cambridge, I looked
for methods with a Cambridge start and clean notation around the
half-lead, with an emphasis on chunks of right-place notation. Five
possibilities are given below.
&-3-4-25-18.104.22.168.8-4-5-4-1,0 1426385079 AB1B2
&-3-4-25-38-347-3.4-4.3-4-1,0 1089674523 AB1B2
&-3-4-25-38-347.2.3-4-1-4-1,0 1089674523 AB1B2
&-3-4-25-1.78-7.8-2-45-4-1,0 1426385079 AB1B2a2
&-3-4-25-8-27.34.1-4-1-4-1,0 1089674523 AB1B2
I was also keen to find a completely right-place method. Following
Richard's assertion that this wouldn't be possible with just quadruple
changes, I experimented a bit with methods similar to those above and
came up with one example:
&-3-4-25-8-27-38-6-347-4-1,2 1648203957 AB1B2
Is it possible to come up with a right-place method that extends
indefinitely with the half-lead property? Seems unlikely but I'm keen
to see what people do. A better example of a right-place method would
also be good.
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