Fred.Bone at dial.pipex.com
Tue Jun 26 13:22:40 UTC 2007
On 25 Jun 2007 at 16:14, Robin Woolley said:
> By way of as 'PS' to my last.
> Fred said: "This algorithm holds only for neighbouring bells, ...... i.e.
> you can
> only apply it one change at a time. For example,
> 324156 gives 21100 = 270
> 624153 gives 51201 = 637"
> Who would want to ring these two changes successively?
Well, probably no-one, especially on a heavy tenor; I was trying to show
that you can't expect it to work on, for example, a list of lead-
head/lead-end pairs, even though the relation between a LH and its LE is
usually a bunch of 2-bell swaps. Perhaps a better example:
123456 gives 00000
165432 gives 04321
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