[r-t] parity

[Fred Bone]

On 25 Jun 2007 at 16:14, Robin Woolley said:

> By way of as 'PS' to my last.
> 
> Fred said: "This algorithm  holds only for neighbouring bells, ...... i.e. 
> you can
> only apply it one change at a time. For example,
> 324156 gives 21100[0] = 270
> 624153 gives 51201[0] = 637"
> 
> Who would want to ring these two changes successively?

Well, probably no-one, especially on a heavy tenor; I was trying to show 
that you can't expect it to work on, for example, a list of lead-
head/lead-end pairs, even though the relation between a LH and its LE is 
usually a bunch of 2-bell swaps. Perhaps a better example:

123456 gives 00000[0]
165432 gives 04321[0]