[r-t] Candidate definition #10a
King, Peter R
peter.king at imperial.ac.uk
Tue Aug 12 21:15:01 UTC 2008
Surely if there are 5040 rows then if we start with rounds (row 0) and
end in rounds (row 5040) then the number of changes (which I like to
think of as the spaces between the rows) is also 5040. If you started on
row 1 (for the sake of argument 2135476) and ended with row 5040
(rounds) then that would be 5039 changes - but 5040 rows. The number of
rows is the same as the number of changes because we traditionally start
from row 0 which is rounds - or am I missing something?
> -----Original Message-----
> From: ringing-theory-bounces at bellringers.net
> [mailto:ringing-theory-bounces at bellringers.net] On Behalf Of
> Don Morrison
> Sent: 12 August 2008 22:07
> To: ringing-theory at bellringers.net
> Subject: Re: [r-t] Candidate definition #10a
>
> On Tue, Aug 12, 2008 at 3:47 PM, Iain Anderson
> <iain.anderson at talentinnovations.co.uk> wrote:
> > There is no problem in the normal case when it starts and
> ends in rounds.
> > But, as you have started to hint, there is a problem if you
> don't start and
> > end in the same change. The 5038 changes of Grandsire that
> was rung in
> > Birmingham would now be legal, but would be 5039 rows of
> Grandsire (or would
> > it?). I would be very interested in starting one blow
> earlier than them so
> > that you get all 5040 rows, but only 5039 changes. What
> would the length be
> > there? I assume 5040, which is fine by me, but I suspect
> not by everyone.
>
> Pondering this further it may be enlightening to reflect on the fact
> that we can't ring a change, we can only ring a row.
>
>
> --
> Don Morrison <dfm at ringing.org>
> "Many people would sooner die than think. In fact they do."
> -- Bertrand Russell
>
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