pabs at cantab.net
Sat Nov 14 09:37:43 UTC 2009
A b-block will give you half the rows with a given pair behind - but
calling a single runs false against the same block.
The Wylde/Johnson magic blocks should work, giving an odd number of
blocks, but I don't think there is sufficient room for manoeuvre to join
them with omits only. Thus I think non-Stedman singles are required.
Anything based on a fixed-course plan will have a course-length that is
a multiple of 24, so the number of courses is a factor of 210. A 21-part
seems the obvious solution - maybe RBG can modify his software?
Robert Bennett said on 13/11/2009 21:59:
> What is the place notation of Orpheus Triples?
> Do you want one with bobs only, singles and bobs only, or s/b/other calls?
> A bob-block plan should work, but the result would be hard to call.
> It may be that something like Hudson's courses of Stedman Triples with a
> twin bob plan, would work.
> Robert Bennett.
> ----- Original Message ----- From: "David Hull" <david at turningcourse.com>
> To: <ringing-theory at bellringers.net>
> Sent: Friday, November 13, 2009 10:22 PM
> Subject: [r-t] Orpheus
>> I've been asked by someone whether I can come up with a composition of
>> Orpheus Triples. Too few bells for me - can one of you mathematical
>> brainboxes help?
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