[r-t] Doubles methods with two hunts and a plain course of 120
Robert Bennett
rbennett at woosh.co.nz
Wed Sep 22 11:19:09 UTC 2010
On Wed 22/09/10 8:27 PM , edward martin edward.w.martin at gmail.com sent:
On 21 September 2010 14:47, Don Morrison wrote:
> On Tue, Sep 21, 2010 at 6:04 AM, Robert Bennett wrote:
>> There are some interesting doubles methods where there are two hunts,
and
>> they (the hunts) cover all possible relative positions (5 x 4 =20)
in each
>> lead. If they do this once in each lead the plain course is 60, but if
they
>> do this twice, the plain lead is 120.
>> An example of the shorter sort is:
>>
>> 5.1.3.5.3.5.3.125.3.5.1.5.3.125.3.5.3.5.3.1 (lead head 12453)
>
> I'm confused. By my reckoning this place notation leads to 35421, not
> 12453 as claimed:
> What am I missing?
According to my reckoning the above PN works if instead of both 125s
you have places in 145
ie with the hunt bells being 1-2 there are 20 different positional
relationships; in the above, the basic principle seems to be to work
this out via slow sixes on the back three bells and to cut these sixes
short where 1-2 would repeat positional relationship.
Eddie Martin
Correct.
It occurs to me that the 3-part 120 of Grandsire Doubles (SBSP x3) is a
method of this type.
RB.
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