[r-t] Doubles methods with two hunts and a plain course of 120

Robert Bennett rbennett at woosh.co.nz
Wed Sep 22 11:19:09 UTC 2010


 

 On Wed 22/09/10 8:27 PM , edward martin edward.w.martin at gmail.com sent:

On 21 September 2010 14:47, Don Morrison  wrote:
 > On Tue, Sep 21, 2010 at 6:04 AM, Robert Bennett  wrote:
 >> There are some interesting doubles methods where there are two hunts,
and
 >> they (the hunts) cover all possible relative positions  (5 x 4 =20)
in each
 >> lead. If they do this once in each lead the plain course is 60, but if
they
 >> do this twice, the plain lead is 120.
 >> An example of the shorter sort is:
 >>
 >> 5.1.3.5.3.5.3.125.3.5.1.5.3.125.3.5.3.5.3.1 (lead head 12453)
 >
 > I'm confused. By my reckoning this place notation leads to 35421, not
 > 12453 as claimed:
 > What am I missing?

 According to my reckoning the above PN works if instead of both 125s
 you have places in 145
 ie with the hunt bells being 1-2 there are 20 different positional
 relationships; in the above, the basic principle seems to be to work
 this out via slow sixes on the back three bells and to cut these sixes
 short where 1-2 would repeat positional relationship.

 Eddie Martin

Correct. 

It occurs to me that the 3-part 120 of Grandsire Doubles  (SBSP x3) is a
method of this type.  

RB. 

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