[r-t] Plain Bob leadheads

[Ian McCulloch]

On Sat, 20 Feb 2021, Martin Bright wrote:

> 
> 
> On Sat, 20 Feb 2021 at 17:18, Philip Saddleton <cantab at saddleton.org.uk> wrote:
>       On Fri, 2021-02-19 at 15:33 +0100, Martin Bright wrote:
>       > Proof:  It's enough to prove it in the case h = (2 4 6 .. n n-1 ... 5
>       > 3) in cycle notation.
>
>       Is it? It depends whether 'Plain Bob Lead Heads' means all of them.
>       It's not true for methods with a 1-lead course, but what if n-1 is not
>       prime?
> 
> 
> I was assuming “Plain Bob lead heads” meant a course of n-1 leads.  You’re right that this is the point at which it doesn’t work in other cases.

But what actaully happens in Royal with 3-lead courses?  A method with 
plain-bob lead ends, 3-lead plain course, and not 12 or 10 lead end change 
would be quite interesting - a novice band can learn 3 leads and ring a 
plain course, and it has some theoretical interest too.  Is this possible?

Cheers,
Ian