[r-t] irregular leadheads

[King, Peter R]

>you are missing
>4532
>5423

>So there are three sets and 6 method types. For (n-1) prime, each set
>consists of (n-2) elements, so there are (n-3)!. More generally, the
>number in each set is the number of integers 1..n-2 that have no common
>factor with n-1.
 
OK I was being dim, now I see the error of my ways

>It's only possible for n=5 - think what the lead end must be.
 
Yup Ijust worked that one out.

>> I hope this has clarified the misunderstanding
>>

>no

Does me being dim clear up the misundertanding? (Don't answer I think I have wasted enough of people'stime on this)
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