[r-t] FCH & Incidence

[Robin Woolley]

Recent correspondence about FCH groups reminds me of another curious 
property, but this time to do with incidence.



It seems that if, say, we have the FCH 4625378 with incidence 8v7 ocurring, 
as it does in Cambridge S8, then we can immediately write down:



a) FCH 4625378 (the inverse), incid. 7v8

and

b) FCH 6452738, incid. 8v4

and

c) FCH 5734268, incid. 4v8



as well as the other four members of the set. In this case, I use the 
convention that the first place bell is in the plain course, the second in 
the false course.



The first of these is well known and is capable of proof but I don't know 
that the second tranformation is so well known.



In summary, if one FCH and its incidence is known, all other FCHs and 
incidence from the treble in the same position can be written down 
straightaway.



Further, this is so for Cambridge S8 but the falsenesses and incidences will 
be identical for all other (LH) group b methods - if any group b method has 
FCH 4625378 8v7, then the other incidences will be the same.



Further again, if one FCH has the pivot bell false against itself, then all 
eight associated FCHs will have the pivot bell self-false. As an example of 
this, see FCH 6274538 3v3 in Cambridge.



Finally, note I say 'seems' at the top of the post. My 'proofs' have not 
been checked by anyone else, so it could all be nonsense. I did find it 
strange that incidence is almost as easy to deal with as FCHs when I first 
met it. It all comes down to clock arithmetic.


Best wishes
Robin.