[r-t] Stedman problem

[Philip Saddleton]

  1342658709E
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9E705836421  2.4.6s.8s.10.11.12.13 (14)
197E5264830  1.5.6.7.9.10.11.12.14s (16)
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Start from rounds as the third row of a slow six


Philip Earis said  on 19/11/2007 06:56:
> I have another Stedman composing problem (a shorter one this time).  Any 
> answers gratefully received.
>
> I want to get from rounds to the row 197E5264830T in as short a time as 
> possible, with the additional constrain that the touch contains back rounds. 
> I'm happy to start from any point in the six, though the change 197E5264830T 
> should be at backstroke, ideally at the six end. I have a preference for the 
> back rounds occuring at a plain six end, but I'm not overly fussy about 
> this.
>
> I can do this in 48 sixes as below (using a conventional start), but I 
> suspect something shorter will be possible.
>
> 1.4s.5.7.8.11.12.13.14.16s.20s (24 sixes to bring up back rounds)
> 1.3.5s.7s.10.11.13.16.19.21s.22 (24 sixes to bring up end point)
>
> Can anyone help?  As ever, there's a pint in it for the best solution.
>
> Philip Saddlton did have a program on his website 
> (http://myweb.tiscali.co.uk/saddleton/stedman/turn.htm) to find the shortest 
> possible turning course between two rows which would have been relevant, but 
> sadly the lnik appears to be broken. 
>