[r-t] Auryn

Alexander Holroyd holroyd at math.ubc.ca
Fri Dec 7 01:32:44 UTC 2012

Maybe the following helps focus on the mystery here: why is it only the 
lead end 14 that works for the TD method?  E.g. why not 12?

On Thu, 6 Dec 2012, Alexander Holroyd wrote:

> Mike's approach is concerned with determining whether there is a true set of 
> leads (or half leads) that give the extent.  In the case of Auryn that is 
> trivially the case, because of the original interpretation in terms of the 
> mirror-symmetric group: two leads of Auryn is half of this group (and a 
> subgroup of index 2), one lead is a quarter.  Your observation below is a 
> manifestation of this.

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