[r-t] Spliced, etc.

Simon Gay Simon.Gay at glasgow.ac.uk
Tue May 22 08:46:55 UTC 2012

In a symmetrical method, a pair of bells that cross at a lead end also
cross at a half lead exactly half a course away. Considering the case of
8 bells: 3-4, 5-6, 7-8 all cross at the same lead end (for 2nds place
methods it's at the end of the course, for 8ths place methods it's at
the lead end 17856342) and therefore also all cross at the same half
lead, in the lead in which all the handbell pairs are ringing their
symmetrical lead. In the course MBKDHFA, not only 7-8 but also 5-6 and
3-4 are ringing symmetrical leads throughout. The remaining bell, 2,
makes a place at the half lead and is therefore ringing the pivot place
bell in every lead. Obviously, for each bell, there is a course of this
kind in which that bell rings all the pivot place bells, but it's only
the course MBKDHFA in which the normal handbell pairs are ringing
symmetrical work in every lead.


On 22/05/2012 07:15, Robin Woolley wrote:
> Apologies in advance for anyone who has posted something along the lines of
> the following, but I only take digests.
> Simon produced some comps. based upon 7-8 crossing at the half-lead in each
> method. I produced some based upon one bell ringing pivots throughout. These
> are the same.We both gave the following:
> (The former can be seen at the start of Philip's comp and the rest is made
> up of suitable fragments of both.)
> The reason for this seems to go as follows:
> Write down the usual coursing order circle but regard it as representing
> place bells.
> In any orientation of the circle, (my) pivot bell is opposite (Simon's)
> swapping pairs.
> e.g., 7-8 swapping =>  2nds place pivot.
> 7-8 becomes 8-6, 8-6 swapping =>  3rds place pivot, etc.
> Best wishes
> Robin
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