[r-t] Stedman Caters touch - 1.5 courses

Daniel Brady danielw.brady at gmail.com
Wed May 21 13:11:40 UTC 2014


My suggestion, again not fitting the original request (too long and not one
of the stated course ends), would be:

231456789
231498765 1 s3 4 6 s8 9 10 11 12 13 (14)
134265798 1 s5 6 7 10 11 s13 (14)
round with a bob at 1

173, inc Queens, 3x *98765, *56789, opening titums, and closing inverted
titums.


On Wed, May 21, 2014 at 11:57 AM, Robert Bennett <rbennett at woosh.co.nz>wrote:

>
>
>         Stedman 1st edition [1903] Chapter IX, pages 101-116, has a table
> of
> starting and homing courses.  On page 102, there is the following
> combination, which seems to be the shortest listed that fits the
> requirements:
>
>         159 (I think)
>
>         231456789
>
>         514362978     1.2.4.5.6.7.11              74 changes
>
>
>         214365879     3.4.6.8.11.12.13         85 changes
>
>         rounds at hand next change.
>
>         Other possible fininshing courses listed for the same starting
> course
> are:
>
>         3,4,5,6,9,14;  (92ch)
>
>         2,4,6,7,8,9,13,15,16;  (94 ch)
>
>         6,8,9,11,13,14,15,16 (99 ch)
>
>
>
>
> ----- Original Message -----
>  From:ringing-theory at bellringers.net
> To:"ringing-theory at bellringersnet"
> Cc:
> Sent:Tue, 20 May 2014 09:38:56 +0000
> Subject:[r-t] Stedman Caters touch - 1.5 courses
>
> A challenge to all you Stedman composers out there - or those with
> good computer programmes for doing the job!
>
> We often ring Stedman Caters on a Sunday morning to fill the remaining
> time before service. Typically, the slot is nearly always too short
> for 2 courses and too long for 1 course.
>
> So, my challenge is - what is the fewest number of calls required for
> a touch that is 1.5 courses long and meets the following criteria?
>
> * between 140 and 170 changes
> * standard Stedman start (4th row of quick six)
> * can come round at handstroke or backstroke
> * has a recognisable course end somewhere within the touch (eg x6978,
> 6x978, 6x879 etc)
>
> Can anyone help?
>
> Thanks,
> Matt.
>
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