[r-t] Tritonian S. Max

[Jack Gunning]

Here is a new London over method with a regular half lead:
Tritonian S. Maximus
&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x0.E, le 2 [d]

To get the regular half lead I made coursing pairs work together in 1-2, 3-4, 5-6, 7-8, and 9-0 under the treble.  This means that: 
- the method is decent in traditional cos, and 
- in tittums c/os you get runs around the quarter/three-quarter lead as well as tittums music around the lead end and half lead.  

Here are a couple of comps:

5040 Tritonian Surprise Maximus, No.1
  234567890ET   N  M  W  O  H
  342567890ET               2
  23456789T0E   T before: 8ths, 6ths, 4ths; 2 In: 4ths, 6ths, 8ths
  436527890ET      -        H      
  654327890ET         -     -
  67452389T0E   -        -   
  234567890ET   s  s        H    
-=14
s=1234
H=10

5040 Tritonian Surprise Maximus, No.2
  234567890ET   N  M  W  O  H
  342567890ET               2
  23456789T0E   T before: 8ths, 6ths, 4ths; 2 In: 4ths, 6ths, 8ths
  65432789T0E      -  -     -
  654327890ET               H      
  67452389T0E   -        -   
  234567890ET   s  s        H      

5040 Tritonian Surprise Maximus, No.3
  234567890ET   N  M  W  O  H
  342567890ET               2
  23456789T0E   T before: 8ths, 6ths, 4ths; 2 In: 4ths, 6ths, 8ths
  65432789T0E      -  -     -
  674523890ET   -           H  
  67452389T0E            -   
  234567890ET   s  s        H    

Each has a large amount of settling time before the mega tittums block (if the method was more familiar, this wouldn’t be as desirable) and then little bell stuff afterwards.  

I used SMC32 to generate the comps by substituting a dummy block for the mega tittums block and looking for a shorter length (3312) using the code:
musthave 1628304T5E79 186T4E203957 O xH 
I added the missing rows as musical exclusions - Mark gave me this idea
So the SMC output for No.1 was:

3312 Tritonian Surprise Maximus, No.1
  234567890ET   N  M  W  H  O  H
  342567890ET                  2
  23456789T0E               -  -
  436527890ET      -     x      
  654327890ET         -        -
  67452389T0E   -           -   
  234567890ET   s  s     x      
Score: 13145
  Musthave blocks 1
  1 reverse rounds
  11 Plain course
  2 Two homes
  52 78s
  9 56s
  18 53246 lbco
  3 35642 lbco
  10 53462 lbco
  11 357642 lbco
  42 pref lbcos
  48 LB6
  82 LB5+
  96 LB4+
  1 Megablock lead end

If you’d like to, feel free to ring it, but I’d rather you didn’t change the name without asking.  

I intend to use the dummy block technique to come up with some Bristol comps on a similar plan.  

Jack


PS here is the proof code:

No. 1
12 Bells
Peal = 10p, q,
10p, q,
8p, s, 6p, r, 6p, q, 9p, q, 6p, r, 6p, s, 
3p, q, 2p, t, 
6p, q, 3p, q,
2p, q, 5p, q, 2p,
2p, v, v, 2p, t
p=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +2, "  @"
q=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +4, "4 @"
r=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +6, "6 @"
s=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +8, "8 @"
t=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +0, "0 @"
u=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +T, "T @"
v=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +1234, "s @“

No.2
12 Bells
Peal = 10p, q,
10p, q,
8p, s, 6p, r, 6p, q, 9p, q, 6p, r, 6p, s, 
3p, q, 2p, q, 3p, q,
6p, t,
2p, q, 5p, q, 2p,
2p, v, v, 2p, t
p=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +2, "  @"
q=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +4, "4 @"
r=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +6, "6 @"
s=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +8, "8 @"
t=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +0, "0 @"
u=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +T, "T @"
v=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +1234, "s @“

No.3
12 Bells
Peal = 10p, q,
10p, q,
8p, s, 6p, r, 6p, q, 9p, q, 6p, r, 6p, s, 
3p, q, 2p, q, 3p, q,
2p, q, 3p, t, 8p, q, 
4p, v, v, 2p, t
p=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +2, "  @"
q=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +4, "4 @"
r=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +6, "6 @"
s=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +8, "8 @"
t=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +0, "0 @"
u=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +T, "T @"
v=&3x3.4x2x3.4x2.5.2x2.7.4x6.9.8x.0.e, +1234, "s @"