[r-t] Bobs only Stedman Triples

[Mark Davies]

Andrew writes,

> An example of group [6.26] has elements 
> 1234567 2341657 3412567 4123657
> so can form 4 1-part blocks, 2 2-part blocks or 1 4-part block.

For sure; so I suppose if the Hamiltonian decomposes into a single 
4-part block you have a peal immediately, but if not there's not much 
chance of joining the separate blocks?

Your paper says you've found at least one cycle for this group - 
presumably this wasn't a peal? What do you think the chances of finding 
one that does work are? An exact four-part would be rather lovely!

MBD