[r-t] Common Grandsire singles in Oxford Bob Triples
Philip Saddleton
pabs at cantab.net
Sun Jan 4 12:11:33 UTC 2009
Don Morrison said on 03/01/2009 16:55:
> On Sat, Jan 3, 2009 at 11:22 AM, Don Morrison <dfm at ringing.org> wrote:
>> That latter property would come for free if the composition were
>> structured as a two part with a single half-way and end, right?
>
> Err, no, on reflection I don't think that's quite right. If it has
> only two singles, and they are half-way and end, then I think it has
> every row once each at hand and back. Have I got it right now?
On reflection, further proof is required - there might be rows repeated
within each half, but omitted in the other. But I don't think this is
possible.
To answer the original question:
10080 Oxford Bob Triples
234567 1 2 3 4 5
----------------------
236457 - - | | | |
342657 s | | | |
247365 - - |A | | |
547236 s | |B | |
723564 s - - | | | |
---------------------- | |C |
523467 - - | | |D
---------------------- | |
752463 A | |
253467 - | |
---------------------- | |
425367 B | |
---------------------- |
342567 B |
----------------------
423 D
----------------------
345267 C
----------------------
734265 A
324567 - s
----------------------
Repeat
Contains each row at hand and back.
(a 24-part with bob omitted every fourth part starting with 3rd, and s
half-way and end)
--
Regards
Philip
http://myweb.tiscali.co.uk/saddleton/
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